in a triangle ABC, right angled at A, if BC =√2 , AB= AC= 1, find out all the six trignomatrical ratios of angle B
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3
Answer:
Step-by-step explanation:
sin=1/root2
cos =1/root2
tan=1
cosec=root2
sec=root2
cot=1
Answered by
2
Step-by-step explanation:
BC = root 2 (given)
Ab = Ac = 1 (given)
Sin C = AB/BC = 1/ root 2
Cos C = AC/BC = 1/root 2
Tan C = AB/AC = 1/1
Sec C = BC/AC = root 2/1
Cosec C = BC/AB = Root 2/1
Cot C = AC/AB = 1/1
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