in a triangle ABC right angled at b a c is equal to 20 cm and tan ACB is equal to 3 upon 4 calculate the measures of a b and b c
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Answer: ab = 12 cm ; bc = 16 cm
Step-by-step explanation:
Tan ACB = 3/4
Tan ACB = opposite side/adjacent side = 3/4 = AB/BC
AB = 3 parts BC = 4 parts
By Pythagoras theorem:
AB² + BC² = AC²
Since 3/4 is a ratio:
3² + 4² = AC²
25 = AC²
AC = √25 = 5 parts [consider only positive root]
Given, AC = 20 cm
AC=== 5 parts = 20 cm
1 part = 20/5 = 4 cm
AB = 3 parts = 3*4 = 12 cm
BC = 4 parts = 4*4 = 16 cm
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