Question

In a triangle ABC right angled at B,A point D lies on BC such that BD = 1cm and AD = Bc find Ac​

Answer 1

Answer:

it is correct answer

it is done

Answer 2

AC = $\sqrt{2x^{2} + 1}$ cm

Step-by-step explanation:

See the attached figure.

Assume that AB = x cm.

Now, given that angle B = 90°, and BD = 1 cm and AD = BC.

We have to find AC.

Now, from Δ ABD, using Pythagoras Theorem, we can write

AD² = AB² + BD² = x² + 1

⇒ BC² = x² + 1

Again, from Δ ABC, using Pythagoras Theorem, we can write

AC² = AB² + BC² = x² + (x² + 1) = 2x² + 1

⇒ AC = $\sqrt{2x^{2} + 1}$ cm (Answer)