In a triangle ABC, right angled at B, AB=24 cm, BC=7 cm. Determine: secA.
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In Δ ABC, B is at right angle.
Given, AB=24cm
BC=7cm
using Pythagoras theorem
AB
2
+BC
2
=AC
2
⇒(24)
2
+(7)
2
=AC
2
⇒AC=
(24
2
)+(7)
2
=
576+49
=
625
⇒AC=25CM
(i)sin A=
AC
BC
=
25
7
cos A=
AC
AB
=
25
24
(ii)sin C=
AC
AB
=
25
24
cos c=
AC
BC
=
25
7
Step-by-step explanation:
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