Question

In a triangle abc right angled at b.ab=4cm and ac+bc=8cm. find the values of Sin c, Cos c and Tan c

Answer 1

Answer:

Step-by-step explanation:

First we have to find all the sides of triangle.

AB is 4cm

BC + AC is 8cm

Let AC length be x

AC + BC = 8

BC = 8-x

Applying pythagoras theorem

AC^2 = AB^2 + BC^2

x^2 = (4)^2 + (8-x)^2

x^2 = 16 + 64 + x^2 - 16x

x^2 will be cancelled

Therefore

16x = 80

X = 5

Hence AC is 5cm BC is 8-5 = 3cm

Now sin C = AB/ AC = 4/5

Cos C = BC/ AC = 3/5

Tan C = AB/ BC = 4/3

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