In a triangle ABC right angled at B, AB = 5 cm and AC = 10 cm. Determine ∠ BAC and ∠ BCA.
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Aɴsᴡᴇʀ~❤️
In ΔABC, <B = 90°
= AB = 5cm
= AC = 10cm
= Sin θ = 5/10 = 1/2
= <BCA = sin^{-1}sin
−1
(1/2) = 30°
= <BCA = 30°
= <BAC = 90° - <BCA (30°)
= <BAC = 90° - 30° = 60°
= <BAC = 60°
∴ <BCA = 30° and <BAC = 60°
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