in a triangle ABC, right angled at B, AC=5inches and angle A 60⁰ find sin A
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1
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Given:
△ABC is right angled at C, ∠B=60
∘
∠C=90
∘
We know that,
In triangle ABC, ∠A+∠B+∠C=180
∘
60
∘
+∠A+90
∘
=180
∘
∠A=30
∘
We have,
sinA=
AB
CB
sin30
∘
=
15
CB
2
1
×15=CB
CB=7.5 units
From Pythagoras theorem,
AB
2
=AC
2
+BC
2
15
2
=AC
2
+(
2
15
)
2
AC
2
=225−(
4
225
)
AC
2
=225(
4
3
)
AC=
2
15
3
units
Answered by
0
Step-by-step explanation:
इन ट्रायंगल एबीसी राइट एंगल एबीसी फंक्शन एंड एंगल ए 60 find sin a
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