Question

in a triangle ABC,right angled at B ,BD isDrawn prependicular to ac prove ABC=C​

Answer 1

Answer:

Given, ∠ABC=90  

∘

 and ∠CDB=90  

∘

 

In △ABC,

∠BAC+∠ABC+∠ACB=180  

∘

 

∠BAC+90  

∘

+∠ACB=180  

∘

 

∠BAC+∠ACB=90  

∘

...(I)

In △CBD,

∠CBD+∠CDB+∠BCD=180  

∘

 

∠CBD+90  

∘

+∠BCD=180  

∘

 

∠CBD+∠BCD=90  

∘

...(II)

Equating I and II

∠BAC+∠ACB=∠CBD+∠BCD

∠BAC=∠CBD (Since, ∠ACB=∠BCD)

Step-by-step explanation: