Math, asked by manujayatri, 5 months ago

In a triangle ABC, right angled at B. If cosec C = 2 then find sec A?
pls help i have an exam now
i need it now i will mark u as a brainlist

Answers

Answered by sakunthalac56
1

A+90°+C=180°

=>A+C=90°

sinB

secAsinC−tanAtanC

=(secAsinC−

cosA

sinA

×

cosC

sinC

)÷sin90°

=(

cosA

sinC

cosA

sinA

×

cosC

sinC

)

=(

cosA

sin(90°−A)

cosA

sinA

×

cos(90°−A)

sin(90°−A)

)

=

cosA

cosA

cosA

sinA

×

sinA

cosA

=1−1

=0

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