Question

In a triangle ABC, Right angled at B if cot A = 1/√3 to the value of cos A +sinA/sinA​

Answer 1

Answer:

√3/3(1+√3)

Step-by-step explanation:

CotA = 1/√3

=> CosA/SinA = 1√3

=>CosA +SinA/SinA = 1+√3/√3

= √3(1+√3)/√3×√3

=√3/3(1+√3)