in a triangle abc right angled at b if sin (A - C ) = 1/2 then angle a and c respectively are
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b is right angle that means b=90°
from triangle
A+B+C= 180°
put value of B we get
A+C= 90°...... equation 1
from qus
sin (A-C) = 1/2
sin (A-C)= sin(30°)
comparing
A-C= 30°....... equation 2
solving eqn 1 and eqn 2
we get A= 60°
B= 30°
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