in a triangle ABC, right angled at B if Tan A= 1/√3 find SinA Cos C+ Cos A Sin C
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Answer:
In triangle ABC , B = 90°
and we know that A+ B+ C = 180°
so A+C = 90°
sinA cosC + cosA sin C = sin ( A+C)
= sin 90°= 1
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