Question

In a triangle abc, right angled at B,ifab=4,BC=3, find all the six trigonometric ratios of

Answer 1

We have, AB = 4 and BC = 3.

By Pythagoras theorem, we have 

AC2=AB2+BC2

⇒AC=AB2+BC2

⇒AC=42+32=25=5

When we consider the t-ratios of ∠A, we have 

Base = AB = 4, Perpendicular = BC = 3, Hypotenuse = AC = 5.

∴sinA=ACBC=53,cosA=ACAB=54,tanA=ABBC=43

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Answer 2

Here's your answer dear ☺️