Question

In a triangle ABC, right angled at C, cos B = 1/2, then the value of sin A cos B + cos A sin B is

a.0
b.1/2
c.3/4
d.1​

Answer 1

Answer:

c is the correct answer

please mark as brainliest if you found this answer helpful

Answer 2

Answer:

Answer is 1

Step-by-step explanation:

sinAcosB+cosAsinB=sin(A+B)

and In triangle A+B+C=180 and angle C=90

∴A+B=90

sin90  

∘

=1