In a triangle ABC ,right angled at C , if tan A= 1 \ ( 1 \√3) , Find the value of sin A - cos B +cos A . sin B .
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1
Answer:
answer=1
Step-by-step explanation:
tanA=1/(1/√3)
tanA=√3
A=60
B=30
sinA=√3/2
sinB=1/2
cosA=1/2
cosB=√3/2
(√3/2)(1/2)-(√3/2)(1/2)
=(√3/4)-(√3/4)
=1
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