In a triangle ABC, right-angled at C, in which AB = 29 units, BC = 21 units and ∠ABC = Ө. Determine the values of
(a)Cos2Ө + sin2Ө
(b)Cos2Ө – sin2Ө
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22
Answer:
1, 41/841
Step-by-step explanation:
Given, AB = 29 units, BC = 21 units, ∠ABC = Ф.
By Pythagoras theorem, we get
⇒ AB² = AC² + BC²
⇒ AC² = AB² - BC²
= (29)² - (21)²
= 400
AC = 20 units.
∴ cosФ = BC/AB
= 21/29.
∴ sinФ = AC/AB
= 20/29
(i) cos²Ф + sin²Ф
= (21/29)² + (20/29)²
= (441 + 400)/841
= 1
(ii) cos²Ф - sin²Ф
= (21/29)² - (20/29)²
= (441 - 400)/841
= (41/841)
Hope it helps!
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