Math, asked by hackerloveworld, 2 months ago

in a triangle abc right angled at c ...write the ratio of sin c cos c tan c​

Answers

Answered by shraddhasanap2007
0

Step-by-step explanation:

90

he he he

ihopeuse

Answered by CUTExCHIRAG
2

Answer:

Here ∠CAB is an acute angle. Observe the position of the sides with respect to angle A.

- BC is the opposite side of Angle A.

- AB is the adjacent side with respect to angle A.

- AC is the hypotenuse of the right angled triangle ABC.

The trigonometric ratios of the angle A in the right angled triangle ABC can be defined as follows.

sinA=

Hypotenuse

SideoppositetoangleA

=

AC

BC

cosA=

Hypotenuse

SideadjacenttoangleA

=

AC

AB

tanA=

SideadjacenttoangleA

SideoppositetoangleA

=

AB

BC

cscA=

SideoppositetoangleA

Hypotenuse

=

BC

AC

secA=

SideadjacenttoangleA

Hypotenuse

=

AB

AC

cotA=

SideoppositetoangleA

SideadjacenttoangleA

=

BC

AB

Now let us define the trigonometric ratios for the acute angle C in the right angled triangle, ∠ABC=90

o

Observe that the position of the sides changes when we consider angle 'C' in place of angle A.

sinC=

AC

AB

cosC=

AC

BC

tanC=

BC

AB

cscC=

AB

AC

secC=

BC

AC

cotC=

AB

BC

dam sure with my answer

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