In a triangle ABC , side BC is produced to D ∠A = 45 degree and exterior angle ACD=115 degree . Find angles ∠B and ∠BCA
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Step-by-step explanation:
D = A + B(EXTERIOR ANGLE PROPERTY)
115 = 45 + B
B=115-45 = 70
A+B+BCA = 180(Angle Sum Property)
70+45+BCA=180
BCA = 180 - 115
BCA = 65
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