Question

In a triangle ABC , side BC is produced to D ∠A = 45 degree and exterior angle ACD=115 degree . Find angles ∠B and ∠BCA

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Answer 1

Answer:

Step-by-step explanation:

D = A + B(EXTERIOR ANGLE PROPERTY)

115 = 45 + B

B=115-45 = 70

A+B+BCA = 180(Angle Sum Property)

70+45+BCA=180

BCA = 180 - 115

BCA = 65