Question

IN A TRIANGLE ABC SIGMA tanA=πtanA then sigma cotAcotB=?​

Answer 1

A + B + C = π (angle sum property of ∆)

cot(A + B + C) = cot π = ∞ = x/0

(sigma cotA - ΠcotA)/sigma cotAcotB = x/0

i.e.

sigma cotAcotB = 0