Question

in a triangle ABC sin A - cos B = cos c then angle B is​

Answer 1

Answer:We have, sinA−cosB=cosC

We have, sinA−cosB=cosC⇒sinA=cosB−cosC

We have, sinA−cosB=cosC⇒sinA=cosB−cosC⇒2sin 2A Acos 2A=2sin 2A cos( 2B−C)⇒cos 2

A =cos( 2B−C)

[∵sin 2A=0]

[∵sin 2A=0]⇒2

[∵sin 2A=0]⇒2A= 2B−C⇒A=B−C

⇒A=B−CBut A+B+C=π

⇒A=B−CBut A+B+C=πTherefore, 2B=π⇒B= 2π

⇒A=B−CBut A+B+C=πTherefore, 2B=π⇒B= 2π

Answer 2

Answer:

Here is the answer for your question in the above attachment

Step-by-step explanation:

I hope this helps you