in a triangle ABC ,sum of angle A and angle B is 90°,if sin A = 5/3 .find the value of tan B
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Answer:
tan B = ???
sinA=5/3
Step-by-step explanation:
In ∆ABC we have,
sinA= 5/3 and A + B= 90°
by Pythagoras th.
H^2= p^2+b^2
3^2=5^2+b^2
9=25+b^2
25-9=b^2
16=b^2
√16=b
4=b
Now,
tan B=5/4
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