Question

in a triangle abc tanA=1 then prove that 2sinAcosA=1​

Answer 1

Answer:

tanA=1

sinA=1/root2

cosA=1/root2

2.1/root2.1/root2=1

2.1/2=1

1=1

Answer 2

Answer:

tan a =1

= tan45

a=45 degree

$\frac{1}{ \sqrt{2} } \times \frac{1}{ \sqrt{2} } = \frac{1}{2}$

$2 \times \frac{1}{2} = 1$

$\sin(45 ) = \frac{1}{ \sqrt{2} } = \cos(45)$