Math, asked by sarojreddy9977, 11 months ago

in a triangle ABC, tanA + tanB + tanC=6 and tanAtanB=2, then find the values of tanA,tanB and tanC

Answers

Answered by balakrishna40

2

tanA+tanB+tanC=tanA.tanB.tanC

6=2.tanC

tanC=3

& tanA+tanB=6-3=3

tanA=2,tanB=1.

balakrishna40: select as brainliest

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