Question

. In a triangle ABC, the bisectors of angle ABC and angle ACB meet at O. Through A, AP and AQ are drawn parallel
to OB and OC respectively to meet BC produced (on both sides) at P and Q respectively. Show that
the perimeter of AABC is equal to pq​

Answer 1

Step-by-step explanation:

In triangle ABQ ,

Ray BP Bisects angle ABQ

By the property of angle bisector

AB/BQ = AP/pq....1

In triangle, ACQ