In+a+triangle+ABC,+the+internal+angle+bisectors+of+angle+B+and+angle+C+meet+at+O.+Prove+OA+is+the+bisector+of+angle+A
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In ∆ABC by angle sum property we have
2x + 2y + <A = 180° = x+ y + ( <A / 2) .....1
In ∆ BOC we have X + Y + ∆ BOC= 180°
From
1) ∆BOC is =180° -90°+( <A /2) - <BOC= 90° + (<A+/2)
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