Question

In a triangle ABC, the internal bisector of B and C meet at P and the external bisector of B and C meet at Q, prove that angle BPC+angle BQC=180°
-Can I solve this like when I draw the digram it becomes like BPCQ a quadrilateral so the sum of opposite angles of a quadrilateral is 180° then hence proved.
Please tell me can I solve it like this?

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

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