In a triangle ABC the midpoint of BC is (2,1) and the centroid (0,3) . The vertex A is
A. (2, 4)
B. (4, -7)
C. (-4, -7)
D. (-4, 7)
Answers
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1
coordinate of centroid=
(x1+x2+x3)/3=. 0 => x1+x2+x3= 0 .........,...(1)
(y1+y2+y3)/3= 3 => y1+y2+y3= 9 .............(2)
again coordinate of mid pint of BC
(x2+x3) /2= 2 => x2+ x3= 4 ......,......(3)
( y2+y3)/ 2= 1 =>. y2+y3= 2 ............(4)
from (1) and (3)
x1= 0-4= - 4
from (2) and (4)
y1= 9-2= 7
therefore coordinate of A: ( -4 7)
option (D) is correct
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