In a triangle ABC, the sides ab and ac are produced to P and Q respectively the bisectors of Angle PBC and angle QCB intersect at a point O prove that angle BOC 90 degree minus angle A / 2
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I don't wanna do this again
udit7586:
are question theek se padh last mein 90 degree +nahi - hai
or starting mein the bisectors of angle b and angle c the sides ab and ac are produced hai read tge question properly
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