Question

In a triangle ABC the value of cos A+cos B+cos C is always___.(>1,<1,<0,>0)​

Answer 1

Answer:

C is always ≥1

Step-by-step explanation:

with equality attained only by the equilateral triangle , along the same lines cos A + cos B + cos C ≥ 1 (3) also follows . Equality is attened by a degnerate triangle with an angel equal to π

Answer 2

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