Question

in a triangle abc, twice angle A equals thrice angle B equals six times angle C. find the angles

Answer 1

Let every angle be in terms of C

C=C

B=2C(3B=6C)

A=3C(2A=6C)

So, by anggle sum property,

A+B+C=180°

3C+2C+C=180

6C=180

C=30

B=60

A=90

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Answer 2

2A=3B=6C=k (say)
Therefore,
A = k/2
B = k/3
C = k/6

Using Angle sum property,
A + B + C = 180°
k/2 + k/3 + k/6 = 180°
(3k + 2k + k)/6 = 180°
k = 180°


Therefore,
A = k/2 = 90°
B = k/3 = 60°
C = k/6 = 30°

Verification:

A + B + C = 180°

Hence, verified.