In a triangle ABC, what will be the value of tanA + tanB + tan C ?
(b) 0
tan Atan B. tan C
(d)-1
(a) 1
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Answer:
∵ A, B and C are the angles of a triangle
∴A+B+C=π
∴tan(A+B+C)=tanπ=0
⟹
1−tanAtanB−tanBtanC−tanCtanA
tanA+tanB+tanC−tanAtanBtanC
=0
tanA+tanB+tanC=tanAtanBtanC
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