Question

In a triangle abc where CAB =90 and AD perpendicular to BC.show that triangle BDA is similar to triangle BAC

Answer 1

Answer:

To prove: ΔBDA is similar to ΔBAC

Proof:

In triangle BDA and BAC,

∠BDA = ∠BAC  [both 90°]

∠B = ∠B [common angle]

Hence by Angle-Angle [AA] Criterion,

ΔBDA  is similar to ΔBAC

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