In a triangle abc,write cos(b+c/2) interms of angle a
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A + B + C = 180
B + C = 180 - A
Dividing by 2
B + C/2 = 90-A/2
cos (B + C / 2) = cos (90-A/2)
= sin A/2
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Answer:
A + B + C = 180
B + C = 180 - A
Dividing by 2
B + C/2 = 90-A/2
cos (B + C / 2) = cos (90-A/2)
= sin A/2
A + B + C = 180
B + C = 180 - A
Dividing by 2
B + C/2 = 90-A/2
cos (B + C / 2) = cos (90-A/2)
= sin A/2
A + B + C = 180
B + C = 180 - A
Dividing by 2
B + C/2 = 90-A/2
cos (B + C / 2) = cos (90-A/2)
= sin A/2
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