Math, asked by duddekuntavenkatajat, 6 months ago

In a triangle ABC x + y + 2 = 0 is the perpendicular bisector of side AB and it meets AB at (-1, -1). If x – y – 1 = 0 is perpendicular bisector of side AC and it meets AC at (2, 1) and P is mid point of BC then distance of P from ortho centre of triangle ABC

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Answered by simiandfg

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i didn't understand this

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