In a triangle ABC ,Z is the mid point of BC. If BX and CY are perpendicular to a line through A then prove that XZ=YZ
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From the diagram attached, since bx and cy are perpendiculars to a line passing through the vertex a, it follows that xy is parallel to bc
Again, from the diagram, bx = cy
Angle xbz = angle ycz = 90 degrees
Since z is the mid-point of bc, it follows that bz = zc
From the forgoing, triangle xbz is congruent to triangle ycz (SSS)
Therefore, xyz Step-by-step explanation:
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