In a triangle ABC, ZA = 90°. AB = 3 cm. AC = 4 cm. Find BC.
Answers
Answer:
In triangle ABC, AB = c = 3, AC = b = 4 and <BAC = 60 deg. What is BC = a?
We can apply the cosine formula
a^2 = b^2 + c^2 - 2bc cos C
= 4^2+3^2–2*4*3*cos 60
= 4^2+3^2–2*4*3*0.5
= 16+9–12
= 13
BC = a = 13^0.5 = 3.605551275 cm
Answer:
Given:
In triangle ABC.
m∠ B=90,
AB = 4 cm,
BC = 3 cm
we need to find AC.
Now By Using Pythagoras theorem which states.
"Sum of square of two sides of a right angled triangle is equal to square of the third side."
framing in equation form we get;
\begin{gathered}AC^2 = AB^2+BC^2\\\\AC^2 = 3^2+4^2\\\\AC^2= 9+16\\\\AC^2 =25\end{gathered}AC2=AB2+BC2AC2=32+42AC2=9+16AC2=25
Now taking square root on both side we get;
\begin{gathered}\sqrt{AC^2} = \sqrt{25} \\\\AC =5\ cm\end{gathered}AC2=25AC=5 cm
Hence The length of side AC is 5 cm.