In a triangle ABCD, question 3
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4
LCM OF 15,10,6 is 60
so 15×4 = 10×6 = 6 ×10
A = 4
b= 6
c= 10
A + b+ c = 20
take multiple 20×9
soA= 4×9 =36
b = 6× 9 = 54
c = 10×9 = 90
so 15×4 = 10×6 = 6 ×10
A = 4
b= 6
c= 10
A + b+ c = 20
take multiple 20×9
soA= 4×9 =36
b = 6× 9 = 54
c = 10×9 = 90
mishrajalaj030peppfc:
LCM nikalne aata haii
but the addition of angles must be 180°
but your answer is wrong
yes now that u have given angles it is more clear thanks
check it
Answered by
1
let A=B=C=x
A=×/15
B=×/10
C=×/6
then,according to the question
A+B+C=180
×/15+×/10+×/6=180
2×+3×+5×/30=180
10×=180×30
×=180×30÷10
×=540
A=×/15=540/15=36
B=×/10=540/10=54
C=×/6=540/6=90
A=×/15
B=×/10
C=×/6
then,according to the question
A+B+C=180
×/15+×/10+×/6=180
2×+3×+5×/30=180
10×=180×30
×=180×30÷10
×=540
A=×/15=540/15=36
B=×/10=540/10=54
C=×/6=540/6=90
thanks
your answer is understandable better
can I follow you for more help
ya why not
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