Question

In a triangle ac=bc and angleA=50° then angle C is

Answer 1

△ABC is isosceles with AC=BC.

Therefore, ∠A=∠B

∠A+∠B+∠C=180∘

∠A+∠A+∠C=180°

2×50°+∠C=180°

∠C=80°(Ans)

Answer 2

as it is given that ac = bc then it clear that it is a isosceles triangle okh !

and you very well know that in isosceles ∆ angles opposite equal sides are themselves equal, an isosceles triangle has two equal angles (the ones opposite the two equal sides).

Hence

/_ ABC = /_BAC

and angle A = 50° (given)

Hence , by the properties of isosceles ∆

/_B=/_A

i.e 50°

and you know that 50° + 50° = 100°

and by angle sum property of ∆ :-

our /_C will be 100° - 180° i.e 80°

.
. . our /_C = 80°

just simple buddy !!!

but a little bit difficult to type !!!;)