Math, asked by tejas22feb, 7 months ago

In a triangle,ad/bc=aeec, angle adc=60, angle bac=40, then angle bca=

Answers

Answered by sailuvenkatneelam199
0

Step-by-step explanation:

I think your question is somewhat wrong I have answered how I have understood.

Angle ACD is an exterior angle of Triangle ABC,

Angle ACD=60°

Angle BAC=40°

Angle BCA=?

In Triangle ABC, Angle ACD is Exterior angle.

Angle ACD=Angle ABC+Angle BAC..... property of remote interior angle theorem.

Angle ABC= Angle ACD—AngleBAC

Angle ABC=60—40

Angle ABC=20°

Now,

Angle ABC+Angle BAC+Angle BCA=180°....Sum of all angles of an triangle is 180°

20+40+Angle BCA=180

Angle BCA= 180—60

Angle BCA=120°

Hope this answer helps you

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