in a triangle an exterior angle at a vertex is 85⁰and its one of the interior opposite angles is 45⁰.find the angle of the triangle
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Answer:
In ∆ ABC
Angle ACD=85°
Let's Suppose Angle BAC=45°
So, Angle CBA= measure of Angle ACD - measure of Angle BAC
Angle CBA=85°-45°=40°
Sum Of All Angles Of Triangle=180°
Angle BAC+Angle CBA+Angle BCA=180°
45°+40°+x =180°
85°+x=180°
x=180°-85°=95°
All Angles Found
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