In a triangle, an exterior angle at a vertex is 95-degree celsius and its one of the interior opposite angles is 55-degree celsius. Find all the angles of a triangle.
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Step-by-step explanation:
We know that the sum of interior opposite angles is equal to the exterior angle. Hence, for the given triangle, we can say that: ∠ABC+ ∠BAC = ∠BCO 55° + ∠BAC = 95° ∠BAC= 95°– 95° ∠BAC = 40° We also know that the sum of all angles of a triangle is 180°. Hence, for the given △ABC, we can say that: ∠ABC + ∠BAC + ∠BCA = 180° 55° + 40° + ∠BCA = 180° ∠BCA = 180° –95° ∠BCA = 85°
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