in a triangle an exterior angle at a vertex is 95 degree and its one of the interior opposite angle is 55 degree find all the angle of the triangle
Answers
Answered by
40
Hi ,
In a triangle an exterior angle at a vertex is
equal to sum of interior opposite angles.
Let three angles are A , B and C ,
according to the problem given,
exterior angle at C = 95
let <B = 55
exterior angle at C = <A + <B
95 = <A + 55
95 - 55 = <A
<A = 40
sum of the angles in a triangle = 180°
<A + <B+ <C = 180
40 + 55 + <C = 180
95 + <C = 180
<C = 180 - 95
<C = 85°
I hope this helps you.
:)
In a triangle an exterior angle at a vertex is
equal to sum of interior opposite angles.
Let three angles are A , B and C ,
according to the problem given,
exterior angle at C = 95
let <B = 55
exterior angle at C = <A + <B
95 = <A + 55
95 - 55 = <A
<A = 40
sum of the angles in a triangle = 180°
<A + <B+ <C = 180
40 + 55 + <C = 180
95 + <C = 180
<C = 180 - 95
<C = 85°
I hope this helps you.
:)
Answered by
6
let ABC the triangle
where C is produced to D
angle ACD now ext angle=95degrees
one of opp. side is 55
A/Q,
ACD=CAB+ABC (EXT ANGLE FORMULA)
95=55+ABC
ABC=40DEGREE
NOW,
CAB+ACB+ABC=180 (ANGLE SUM PRO.)
95+ACB=180
ACB=85 degree
where C is produced to D
angle ACD now ext angle=95degrees
one of opp. side is 55
A/Q,
ACD=CAB+ABC (EXT ANGLE FORMULA)
95=55+ABC
ABC=40DEGREE
NOW,
CAB+ACB+ABC=180 (ANGLE SUM PRO.)
95+ACB=180
ACB=85 degree
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