Question

in a triangle and exterior angle at a vertex is 105 degree and one of its interior opposite angle is 55 degree find all the angles of a triangle​

Answer 1

55⁰ , 50⁰ , 75⁰

exterior angle = sum of opposite interior angles

55⁰ is one opposite interior angle and let the other angle be x

105⁰ = 55 + x

x = 105 - 55 = 50⁰

let the other angle be y

x + y + 55⁰ = 180⁰ (asp)

50⁰ + y + 55⁰ = 180⁰

105⁰ + y = 180⁰

y = 180 - 105 = 75⁰

the three interior angles of the triangle are 55 , 50 and 75