Question

In a triangle, angle A=2angle B and Angle A=1/3angle c find measures if all three angle

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Answer 1

Ur Answer:-

let the angle B be x then,

angle A = 2 angle B

2x

also,

angle A = 1/3 of angle C

3 angle A = angle C

angle C=3 multiply 2x

6x

Now,

In triangle ABC

angle A + angle B + angle C = 180

2x+x+6x = 180

9x= 180

x = 20

hence,

angle A =2x = 2 multiply 20 = 40

angle B =x = 20

angle C= 6x = 6 multiply 20= 120

$hope... it....helps...you$

Answer 2

According to the condition in the △ABC, 2∠A=3∠B=6∠C

According to the condition in the △ABC, 2∠A=3∠B=6∠C⇒∠A=3∠C and, ∠B=2∠C

According to the condition in the △ABC, 2∠A=3∠B=6∠C⇒∠A=3∠C and, ∠B=2∠CSum of interior angles of the triangle is 180o

According to the condition in the △ABC, 2∠A=3∠B=6∠C⇒∠A=3∠C and, ∠B=2∠CSum of interior angles of the triangle is 180oHence ∠A+∠B+∠C=180o

According to the condition in the △ABC, 2∠A=3∠B=6∠C⇒∠A=3∠C and, ∠B=2∠CSum of interior angles of the triangle is 180oHence ∠A+∠B+∠C=180o⇒3∠C+2∠C+∠C=180o

According to the condition in the △ABC, 2∠A=3∠B=6∠C⇒∠A=3∠C and, ∠B=2∠CSum of interior angles of the triangle is 180oHence ∠A+∠B+∠C=180o⇒3∠C+2∠C+∠C=180o⇒∠C=30o

According to the condition in the △ABC, 2∠A=3∠B=6∠C⇒∠A=3∠C and, ∠B=2∠CSum of interior angles of the triangle is 180oHence ∠A+∠B+∠C=180o⇒3∠C+2∠C+∠C=180o⇒∠C=30o∴∠A=900,∠B=60o,∠C=30o