In a triangle angle A= angle C,B=120degree BC=4cm find angle A
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Answer:
according angle sum property of triangle ,
angle A + angle B + angle C = 180°
and angle A = angle B..let it be x .then
x + 120° +x = 180
120 + 2x = 180
2x = 180-120
2x = 40
x = 40/2
x = 20°
thus angle A and C will be 20°
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Answer:
Given : AB = 6 cm, BC = 4 cm. and ∠B = 120°
To construct: Incircle of ΔABC Steps of construction :
(1) Draw a line segment BC = 4 cm
. (2) Construct a ray making an angle of 120° at B of BC. Cut AB = 7 cm.
(3) Join A to C, and obtain ΔABC.
(4) Now bisects ∠ABC and ∠BCA that to intersect at O.
(5) Draw OD ⊥ AC and with O as centre and OD as radius draw a circle which touches three sides of ΔABC. This is the in circle of ΔABC
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