Question

in a triangle angle a:b:c=1:2:4 then. (a^2-b^2)(b^2-c^2)(c^2-b^2)=ka^2b^2c^2 then k=
where a,b,c are sides of triangles
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Answer 1

Answer:

k=90

Step-by-step explanation:

let a=x,b=2x,c=4x,

then a^2b^2c^2=8x^6

(a^2-b^2)(b^2-c^2)(c^2-b^2)=(x^2-4x^2）(4x^2-16x^2)(16x^2-4x^2)=720x^6=90*8x^6=90a^2b^2c^2

tnus,k=90

Answer 2

Please check attachment.