Question

In a triangle angle A is 45° Angle B two times of angle A , find the angle C
(a) 45°
(b) 40°
(c) 80°
(d) 100°

Answer 1

Step-by-step explanation:

Angle A = 45° = x

Angle B = 90° = 2x.

x + 2x + angle C = 180° ( Angle sum property )

45 + 90 + C = 180 degree

Angle C = 180 - 135

= 45°.

Answer 2

In context to questions asked,

we have to determine the value of third angle.

As per Questions,

It is given that,

Value of angle A = 45 degree

Value of angle B = twice as the value of angle A

= 90 degree

As we know that,

Sum of all angles of triangle is 180 degree.

So, let the value of third angle be "x"

So, from above,

$45 + 90 + x = 180 \\ = > 135 + x = 180 \\ = > x = 180 - 145 = {45}^{0}$

Hence, value of third angle will be 45 degree.