In a triangle angles are2x, ( x+30),(x-10) find the angles
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Answered by
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2x+(x+30)+(x-10)=180
4x+30-10=180
4x+20=180
x=180-20/4
x=160/4=40
therefore angles are 80,70,20
4x+30-10=180
4x+20=180
x=180-20/4
x=160/4=40
therefore angles are 80,70,20
Answered by
1
sum of the angles in a triangle is 180degree
2x+x+30+x-10=180
4x+20=180
4x=180-20
4x=160
x=160/4
x=40
first angle=2x=2*40=80
second angle=x+30=40+30=70
third angle=x-10=40-10=30
2x+x+30+x-10=180
4x+20=180
4x=180-20
4x=160
x=160/4
x=40
first angle=2x=2*40=80
second angle=x+30=40+30=70
third angle=x-10=40-10=30
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