Question

In a triangle D is a point on BC such that angle ABD =angle CAD.If AB=5 AD=4 AC=3 find BC

Answer 1

first in triangle ABD from pythagoreos theorem
${ad}^{2} + {bd}^{2} = {ab}^{2}$

${4}^{2} + {bd }^{2} = {5}^{2}$
${bd}^{2} = 25 - 16$
$bd = \sqrt{9 } \\ bd = 3$