Question

in a triangle DE parallel to BC AD =3cm,BD=4cm,AC=14cm find DE
​

Answer 1

Given:

DE∥BG,AD=3cm,BD=4cm and BC=5cm

(i) AE:EC

So, AD/BD=AE/EC ∵DE∥BC

AE/EC=AD/BD

AE/EC=

4

3

AE:EC=3:4

(ii) consider △ADE and △ABC

∠D=∠B

∠E=∠C

∠A=∠A ∵DE∥BC

Therefore, △ADE∼△ABC

Then, DE/BC=AD/AB

DE/5=3/(3+4)

DE/5=3/7

DE=(3×5)/7

DE=15/7

DE=2

7

1

cm.

Answer 2

Step-by-step explanation:

here is your answer dear